- gmatter2012
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What is the units digit of 6^15 - 7^4 - 9^3?
A. 8
B. 7
C. 6
D. 5
E. 4
A. 8
B. 7
C. 6
D. 5
E. 4
Any power of 6 always ends with 6.gmatter2012 wrote:What is the units digit of 6^15 - 7^4 - 9^3?
What I would do is (6 - 1 - 9 )= -4 which is not the answerAnurag@Gurome wrote:Any power of 6 always ends with 6.gmatter2012 wrote:What is the units digit of 6^15 - 7^4 - 9^3?
Now, unit's digit of 7^4 = 1
And, unit's digit of 9^3 = 9
Hence, unit's digit of (7^4 + 9^3) = unit's digit of (1 + 9) = 0
why are we adding here?
Therefore, unit's digit of (6^15 - 7^4 - 9^3) = unit's digit of (6 - 0) = 6
The correct answer is C.
You can either add first then subtract or you can directly subtract.gmatter2012 wrote:What I would do is (6 - 1 - 9 )= -4 which is not the answer
what I cannot understand is why are we adding units digit of 7^4 + 9^3 shouldn't we subtract?
Anurag@Gurome wrote:You can either add first then subtract or you can directly subtract.gmatter2012 wrote:What I would do is (6 - 1 - 9 )= -4 which is not the answer
what I cannot understand is why are we adding units digit of 7^4 + 9^3 shouldn't we subtract?
The order of addition and subtraction doesn't matter what you do as long as you are doing it in proper way.
Now what is your logic of saying -4 is the unit's digit?
Have you ever seen any number whose unit's digit is negative? Or any other digit for that matter?
What is the unit's digit of (66 - 21 - 19)?
Is it -4? Or it is the unit's digit of 26?
(66 - 21 - 19) will always be equal to 26.
It does not mater how you get 26. You can get 26 in any of the following ways...Similarly unit's digit of (some integer with unit's digit 6 - some integer with unit's digit 1 - some integer with unit's digit 9) = 6
- (66 - 21 - 19) = (66 - (21 + 19)) = (66 - 40) = 26
(66 - 21 - 19) = ((66 - 21) - 19) = (45 - 19) = 26
(66 - 21 - 19) = ((66 - 19) - 21) = (47 - 21) = 26
What you have said is correct except that it is not temporary concept. It is how subtraction is carried out. I've shown you the example with 66, 21, and 19. 6 is less than 1 and 9 put together. But we have to subtract 1 and 9 from 6. Hence, we borrow 1 from 6 (the tens digit of 66) and add 10 to 6 (unit's digit of 66). Now our job is to subtract 1 and 9 from (10 + 6) = 16. And we put (16 - 1 - 9) = 6 in the unit's place.My own immature temporary concept : Follow normal algebraic rules with the unit digits and if the units digit comes out negative then subtract from 10.