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We can see that, if x is positive, then |x|+x will equal zero.treker wrote:If y is an integer and y=|x|+x, is y=0?
1) x<0
2) y<1
I do not understand why the solution is D.
It is obvious that 1) is SUF, but what about 2)?
Isn't -1 an integer ?Brent Hanneson wrote:We can see that, if x is positive, then |x|+x will equal zero.treker wrote:If y is an integer and y=|x|+x, is y=0?
1) x<0
2) y<1
I do not understand why the solution is D.
It is obvious that 1) is SUF, but what about 2)?
If x is positive, then |x|+x will have a positive value.
So, if x is negative, y is zero. If x is positive then y is positive. In other words, y is either a positive number or it is zero.
(2) tells us that y<1. Since y is an integer, y must equal 0. So, (2) is sufficient.
I think that since y<1... y can be any number.. how is it that y is necessarily 0.. y can be -5 for all you know.. therefore Statement 2 is not sufficient.Brent Hanneson wrote:We can see that, if x is positive, then |x|+x will equal zero.treker wrote:If y is an integer and y=|x|+x, is y=0?
1) x<0
2) y<1
I do not understand why the solution is D.
It is obvious that 1) is SUF, but what about 2)?
If x is positive, then |x|+x will have a positive value.
So, if x is negative, y is zero. If x is positive then y is positive. In other words, y is either a positive number or it is zero.
(2) tells us that y<1. Since y is an integer, y must equal 0. So, (2) is sufficient.
A for me. If the question were to state that x is an integer, then my answer would be D.treker wrote:If y is an integer and y=|x|+x, is y=0?
1) x<0
2) y<1
I do not understand why the solution is D.
It is obvious that 1) is SUF, but what about 2)?
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