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IMO E

s1) a can be 7/12 and 9/13 as bth are less than 3/4 and grter than 5/11
s2) only 9/13 and 7/12 bth are less than 11/13 and grter than 1/2

IMO E

IMO is definitely E but I did take a lot of time comparing fractions.
@machoman and @phoenix- Some insight please?

Thanks in advance

eaakbari wrote:IMO is definitely E but I did take a lot of time comparing fractions.
@machoman and @phoenix- Some insight please?

Thanks in advance

If ur good in getting out decimals out of fractiocs, that shuld do the trick. i quickly converted them to decimals.

yesterday Pheonix was telling "Remembering/Identifying GMAC Patterns itself is half battle won". Now takeaway is convert them to decimals, then it will be cakewalk.

U may argue how patterns will help u. I would support that if u can get 10-15 laid out patterns, those saved moments culd be invested in DS/Probability based one

eaakbari wrote:IMO is definitely E but I did take a lot of time comparing fractions.
@machoman and @phoenix- Some insight please?

Thanks in advance

here we need to know how many of the three values lie between the given condition , if its only one then yes we can get value of a , if its more than one than insuff

to do so the shortest is cross multiply
in order to compare two fraction either make the denominator common (which is tedius here) or cross mutiply
for eg
5/11 and 9/13
13*5<9*11 so 5/11<9/13;now 3/4 and 9/13....13*3>4*9...so 9/13<3/4
hence 5/11<9/13<3/4
sinliraly 7/12 and 5/11 --->7*11>5*12--->7/12>5/11;and 3/4 , 7/12--->12*3>7*4--->3/4>7/12
hence 5/11<7/12<3/4
so a can be bth 9/13 and 7/12 as bth satifies s1)
similarly one can do for s2)

vishalranka wrote:If a is equal to one of the numbers 5/11, 7/12,9/13 what is the value of a?

1) 5/11 < a < 3/4

2) 11/13 > a > 1/2

Let's focus on comparing fractions.

You can either compare fractions to each other or you can compare each fraction to a simpler one. 1/4, 1/3 and 1/2 are good fractions for comparison.

For (1), for example, 5/11 is less than 1/2. Since 7/12 and 9/13 are both more than 1/2, they fit into the range from that side.

Now let's compare them to 3/4; well, 9/12=3/4, so 7/12 must be less than 3/4 (since 7 < 9). Further, 9/13 must be less than 3/4 (since in 9/13 vs 9/12, 13 > 12).

Accordingly, based on (1), a could be either 7/12 or 9/13.

For (2), 7/12 and 9/13 are both greater than 1/2, so we don't have to worry about the small end of the range.

11/13 is certainly greater than both 9/13 and 7/12 (since 7/12 is < 3/4 and 11/13 > 3/4), so we don't have to worry about the large end of the range.

Accordingly, based on (2), a could be either 7/12 or 9/13.

* * *

So, here's the general rule for comparing positive fractions:

if two fractions have the same denominator, the one with the bigger numerator is greater; and

if two fractions have the same numerator, the one with the bigger denominator is smaller.

Thanks guys that sure does help.

E