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x/y

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Source: — Data Sufficiency |
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by shulapa » Mon Feb 23, 2009 9:33 am
Lets look at each statement separately.

(1) x = 0.5 + y

This does not tell us anything about the values of x and y. Only the relation between them. Therefore, insufficient.

(2) x/y > 1

lets use some numbers

x=2, y=0.5 x/y=4>2
x=-2, y=-0.5 x/y=4>2.

Therefore, insufficient.

(1)+(2)

lets place the first equation in the second:
(0.5+y)/y=0.5/y + 1>1
0.5/y>0

So we know that y>0 therefore, x=y+0.5>0.5

Therefore, C
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Re: x/y

by sanjay_dce » Mon Feb 23, 2009 10:00 am
billyr wrote:Are x and y both positive?

(1) 2x-2y=1

(2) x/y>1



The answer is c, but i thought it should be E .


thanks
stmt1: obviously not sufficient .
stmt 2 : x & y both can be -ve and both could be +ve, only thing it tells that both need to be of same sign and mod x > mod y

using both 1 &2 only option left is both x and y are +ve and X>Y hence C is correct
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Re: x/y

by x2suresh » Mon Feb 23, 2009 8:22 pm
billyr wrote:Are x and y both positive?

(1) 2x-2y=1

(2) x/y>1



The answer is c, but i thought it should be E .


thanks
clearly individual statements not sufficient

combined

2x-2y=1 --> divide by 2y throught out the equation.

x/y-1 = 1/2y

we know that x/y>1 eqn(2)

clearly 1/2y >1 --> y is +ve

if y is +ve clearly from eqn 2x-2y=1
x is +Ve

sufficient

C.
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by sureshbala » Mon Feb 23, 2009 8:53 pm
Clearly each statement alone is not sufficient.

From I: x=y+1

From II: x/y>1

i.e (y+1)/y >1

i.e 1+1/y >1

So y>0.
Since x =y+1, x>0

Hence C is the answer
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by x2suresh » Mon Feb 23, 2009 9:07 pm
sureshbala wrote:Clearly each statement alone is not sufficient.

From I: x=y+1

From II: x/y>1

i.e (y+1)/y >1

i.e 1+1/y >1

So y>0.
Since x =y+1, x>0

Hence C is the answer

how did you get x=y+1 from eqn(1) 2x-2y=1 ??
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by sureshbala » Mon Feb 23, 2009 9:20 pm
Sorry..x = y+1/2. Still the logic remains same
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by luckylucky » Tue Feb 24, 2009 8:06 pm
Are x and y both positive?

(1) 2x-2y=1

(2) x/y>1

Frens please correct me if i am wrong in my approach


1) 2x - 2y = 1

= > x - y = 0.5

Plug in values that satisfy the above equation

a) x = -3 y = -3.5

It satisfies the equation and both x , y <0

b) x = 4 y = 3.5

It satisfies the equation and both x ,y >0

Hence A alone is not sufficient

2) x/y > 1

= > x > y

a) x = 4 y = 3.5 x,y >0

b) x = -3 y = -3.5 x,y < 0

Hence B alone is not sufficient

Combining both A and B

x - y = 0.5 & x > y

a) x = 4 and y = 3.5 x,y > 0

b) x = -3 and y = -3.5 x,y < 0


Hence the answer should be E

I am not able to get C with the above approach . Can someone pleas explain where am i going wrong ?
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by kamu » Sun Mar 01, 2009 6:44 am
luckylucky wrote:Are x and y both positive?

(1) 2x-2y=1

(2) x/y>1

Frens please correct me if i am wrong in my approach


1) 2x - 2y = 1

= > x - y = 0.5

Plug in values that satisfy the above equation

a) x = -3 y = -3.5

It satisfies the equation and both x , y <0

b) x = 4 y = 3.5

It satisfies the equation and both x ,y >0

Hence A alone is not sufficient

2) x/y > 1

= > x > y

a) x = 4 y = 3.5 x,y >0

b) x = -3 y = -3.5 x,y < 0

Hence B alone is not sufficient

Combining both A and B

x - y = 0.5 & x > y

a) x = 4 and y = 3.5 x,y > 0

b) x = -3 and y = -3.5 x,y < 0


Hence the answer should be E

I am not able to get C with the above approach . Can someone pleas explain where am i going wrong ?
exactly!!!!
please explain!!!
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by sureshbala » Sun Mar 01, 2009 6:55 am
luckylucky wrote:Are x and y both positive?

(1) 2x-2y=1

(2) x/y>1

Frens please correct me if i am wrong in my approach


1) 2x - 2y = 1

= > x - y = 0.5

Plug in values that satisfy the above equation

a) x = -3 y = -3.5

It satisfies the equation and both x , y <0

b) x = 4 y = 3.5

It satisfies the equation and both x ,y >0

Hence A alone is not sufficient

2) x/y > 1

= > x > y

a) x = 4 y = 3.5 x,y >0

b) x = -3 y = -3.5 x,y < 0

Hence B alone is not sufficient

Combining both A and B

x - y = 0.5 & x > y

a) x = 4 and y = 3.5 x,y > 0

b) x = -3 and y = -3.5 x,y < 0


Hence the answer should be E

I am not able to get C with the above approach . Can someone pleas explain where am i going wrong ?
Folk, look at the bold statements....

If x/y > 1, then we can conclude that x>y provided x and y are positive. This is what you missed.

Looking at your example (in bold), if x= -3 and y = -3.5 , how can x/y >1? Instead it will be less than...

Hope you got it....
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