BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Factorial -DS

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
Senior | Next Rank: 100 Posts
Posts: 86
Joined: Tue Aug 05, 2008 10:50 am
Thanked: 7 times

by hengirl03 » Wed Aug 20, 2008 9:25 am
After attempting this problem, I got E.



1) x is sum of two distinct single prime numbers

Single prime number 2,3,5,7

12! = 1 x 2 x 3 x 2 x 2x 5x 2x3x7x2x2x2x9x2x5x11x2x2x3

Since x can be 6(a factor) or 12(not a factor), this is insufficient

2.) 0<x>1 <= Is this written correctly? If it is it is insufficient.

Using both 1.) is 2.) together is still insufficient since x can still be 6 or 12.



What's the official answer?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Wed Aug 20, 2008 9:32 am
The thing to add is that 2^x cannot be bigger than 2^10
given 12!=2^10*m with m composed of facctors different from 2

For the 2)
it cannot be 0<x<1 because x would no longer be an integer...
so it is 0<x>1... that is strange could you check because it means x>1

In that case I go for E
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 32
Joined: Sun Jul 06, 2008 11:10 pm
Location: Pakistan
Thanked: 1 times

factorial -DS

by jawad » Thu Aug 21, 2008 3:23 am
hi ,

Regret for mis-reporting, Clue 2 is 0<x<10.

I thought that 2^x has to be 2^10 to evenly divide the 12!. 2^10 would be the max value which can divide. Because thru below breakdown , maximum number of 2's are 10.
12! =

12= 2*2*2*3
11
10=2*5
9
8=2*2*2
7
6=2*3
5
4=2*2
3
2=2*1
1

By that toke , 10 would be max value for 2.

And since clue# 1 tells us that 2-signle digits add up to that value . clue 1 can be sufficent . Isnt it ?

And second option tells same clue in different phrase. SO cant ans be D
Jawad Shah
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1