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Source: — Data Sufficiency |
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by Frankenstein » Sun Jun 12, 2011 8:37 am
Hi,
From(1): x/y + y/x = 2 =>(x^2+y^2)/xy = 2 => (x^2+y^2) -2xy = 0 =>(x-y)^2 = 0.
So, x=y
Sufficient
From(2): xz>yz => (x-y)z>0
If z>0, x>y
If z<0, x<y
Insufficient

Hence, A
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by Anurag@Gurome » Sun Jun 12, 2011 8:44 am
vinayreguri wrote:x & y are +ve numbers. Is x > y
1. x/y + y/x = 2
2. xz > yz
Statement 1: x/y + y/x = 2
Hence, (x² + y²) = 2xy --> (x² + y² - 2xy) = 0 --> (x - y)² = 0
Therefore, x = y

Sufficient

Statement 2: xz > yz
If z is positive, x > y
If z is negative, x < y

Not sufficient

The correct answer is A.
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