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In a marketing survey, 60 people were asked to rank three flavors of ice cream, chocolate, vanilla, and strawberry, in

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by BTGmoderatorDC » Mon Apr 26, 2021 3:23 pm

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In a marketing survey, 60 people were asked to rank three flavors of ice cream, chocolate, vanilla, and strawberry, in order of their preference. All 60 people responded, and no two flavors were ranked equally by any of the people surveyed. If 3/5 of the people ranked vanilla last, 1/10 of them ranked vanilla before chocolate, and 1/3 of them ranked vanilla before strawberry, how many people ranked vanilla first?

A. 2
B. 6
C. 14
D. 16
E. 24


OA A

Source: GMAT Prep
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Source: — Problem Solving |

BTGmoderatorDC wrote:
Mon Apr 26, 2021 3:23 pm
In a marketing survey, 60 people were asked to rank three flavors of ice cream, chocolate, vanilla, and strawberry, in order of their preference. All 60 people responded, and no two flavors were ranked equally by any of the people surveyed. If 3/5 of the people ranked vanilla last, 1/10 of them ranked vanilla before chocolate, and 1/3 of them ranked vanilla before strawberry, how many people ranked vanilla first?

A. 2
B. 6
C. 14
D. 16
E. 24


OA A

Source: GMAT Prep
Total \(=\) Vanilla before Chocolate \(+\) Vanilla before Strawberry \(-\) Vanilla before Both \(+\) Vanilla before neither
\(1 = 1/10 + 1/3 -\) Vanilla before Both \(+ 3/5\)
\(1 - 3/5 = 13/30 -\) Vanilla before Both
\(2/3 = 13/30 -\) Vanilla before Both
Vanilla before Both \(= 1/30.\)

\(1/30\) of \(60 = 2.\)

Therefore, A
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