- cssilverman
- Newbie | Next Rank: 10 Posts
- Posts: 2
- Joined: Mon Apr 11, 2011 8:29 pm
I am still confused about how to compute permutations. Here is an example problem that is causing me trouble:
If a jury of 12 people is to be selected randomly from a pool of 15 potential jurors, and the jury pool consists of 2/3 men and 1/3 women, what is the probability that the jury will comprise at least 2/3 men?
24/91
45/91
2/3
67/91
84/91
If a jury of 12 people is to be selected randomly from a pool of 15 potential jurors, and the jury pool consists of 2/3 men and 1/3 women, what is the probability that the jury will comprise at least 2/3 men?
24/91
45/91
2/3
67/91
84/91


















