ruplun wrote:Of the students who eat in a certain cafeteria , each student either likes or dislikes lime beans and each student either likes or dislikes brussel sprouts. Of these students,2/3 dislike lima beans ; and of those who dislike lima beans , 3/5 also dislike brussel sprouts. How many of the students like brussel sprouts but dislike lima beans?
a. 120 students eat in the cafeteria
b. 40 of the students like lima beans
I guess this question should have been posted in DS and not in PS.
nevertheless, IMO
E .
Reason:
we are required to get the number of students who like brussel sprouts but dislike lima beans.
let x = number of students
number of students who dislike lima beans = (2/3)x
...and...
(3/5) of (2/3)x dislike brussel sprouts.
(1) - jst gives the value of x and hence, we can calculate the people who dislike lima beans and out of those, who like brussel sprouts. but wat about people who like brussel sprouts and same out of those, dislike brussel sprouts.
INSUFFICIENT
(2) - saying the same thing as said in (1).
INSUFFICIENT
combining both , INSUFFICIENT
hence,
E ---------------------------------------
Appreciation in thanks please!!
