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HOw many ways to assign 3 employees in 2 offices

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by mp2437 » Wed Nov 04, 2009 10:45 am
I get 2^3 = 8 possibilities.

Also, I did it the longer way, though it didn't take much time.

Let "|" denote the number of people in rooms A & B. You get these combinations:


123|
12|3
13|2
23|1
1|23
2|13
3|12
|123
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