Speed/Distance

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 138
Joined: Mon May 01, 2017 11:56 pm
Thanked: 4 times

Speed/Distance

by vaibhav101 » Wed Jun 06, 2018 8:52 am

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

A motorcyclist rode the first half of his way at a constant speed. Then he was delayed for 5 minutes and , therefore, to make for the lost time he increased his speed by 10 km/hr. Find the initial speed of the motorcyclist if the distance covered by him is equal to 50 km.

A 36 km/hr
B 48 km/hr
C 50 km/hr
D 62 km/hr
E 55 km/hr
Source: — Problem Solving |

Legendary Member
Posts: 2898
Joined: Thu Sep 07, 2017 2:49 pm
Thanked: 6 times
Followed by:5 members

by Vincen » Fri Jun 08, 2018 2:02 am
vaibhav101 wrote:A motorcyclist rode the first half of his way at a constant speed. Then he was delayed for 5 minutes and, therefore, to make for the lost time he increased his speed by 10 km/hr. Find the initial speed of the motorcyclist if the distance covered by him is equal to 50 km.

A 36 km/hr
B 48 km/hr
C 50 km/hr
D 62 km/hr
E 55 km/hr
Hello vaibhav101.

This is the way I'd solve this PS question.

We have that:

d = 50km.
v_1 - initial velocity
v_2 = v_1+10km/h
t_1 - time first 25km
t_2 = t_1-5 minutes

Since we have to calculate km/h we have to convert 5 minutes to hours. Then 5 minutes is the same as 1/12 hours. Therefore,

t_2=t_1 - 1/12.

Also, we know that v_1*t_1=25 km.

Therefore, we have $$d=v\cdot t\ $$ $$50=v_1\cdot t_1+v_2\cdot t_2\ $$ $$50=v_1\cdot t_1+\left(v_1+10\right)\cdot\left(t_1-\frac{1}{12}\right)\ $$ $$50=25+v_1\cdot t_1-\frac{v_1}{12}+10t_1-\frac{5}{6}$$ $$50=25+25-\frac{v_1}{12}+10t_1-\frac{5}{6}$$ $$\frac{5}{6}=-\frac{v_1}{12}+10t_1$$ $$10=-v_1+120t_1$$ $$\frac{10+v_1}{120}=t_1\ \ .$$ Now, replacing this in the equation d_1=v_1*t_1 we get $$d_1=v_1\cdot t_1\ \ \Rightarrow\ \ 25=v_1\left(\frac{10+v_1}{120}\right)\ \ \Rightarrow\ \ 3000=10v_1+v_1^2$$ $$v_1^2+10v_1-3000=0$$ $$(v_1-50)(v_1+60)=0$$ $$v_1=50\ \frac{km}{h}\ \ \ \ or\ \ \ \ v_1=-60\ \frac{km}{h}.$$
Thereore, the correct answer is the option C.

I hope it is clear enough.

Regards.

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Fri Jun 08, 2018 2:15 am
vaibhav101 wrote:A motorcyclist rode the first half of his way at a constant speed. Then he was delayed for 5 minutes and , therefore, to make for the lost time he increased his speed by 10 km/hr. Find the initial speed of the motorcyclist if the distance covered by him is equal to 50 km.

A 36 km/hr
B 48 km/hr
C 50 km/hr
D 62 km/hr
E 55 km/hr
We can PLUG IN THE ANSWERS, which represent the initial speed.
When the correct answer is plugged in, increasing the speed by 10 kph will enable the cyclist to travel 25 km in 5 fewer minutes.
Since the increase in the speed and the total distance are both multiples of 10, the correct answer is probably C, which also is a multiple of 10.

C: initial speed = 50 kph, higher speed = 50+10 = 60 kph
Time to travel 25 kilometers at a speed of 50 kph = d/r = 25/50 = 1/2 hour.
Time to travel 25 kilometers at a speed of 60 kph = d/r = 25/60 = 5/12 hour.
Time difference = 1/2 - 5/12 = 6/12 - 5/12 = 1/12 hour = 5 minutes.
Success!

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8083
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members

by Scott@TargetTestPrep » Tue Jun 12, 2018 10:15 am
vaibhav101 wrote:A motorcyclist rode the first half of his way at a constant speed. Then he was delayed for 5 minutes and , therefore, to make for the lost time he increased his speed by 10 km/hr. Find the initial speed of the motorcyclist if the distance covered by him is equal to 50 km.

A 36 km/hr
B 48 km/hr
C 50 km/hr
D 62 km/hr
E 55 km/hr
We can let his speed for the first half of the 50-km trip be r km/hr; thus, his speed for the second half is (r + 10) km/hr. Since 5 min = 1/12 hr and the time of the first half of the trip is equal to the time of the second half plus the 5-minute delay, then we can create the equation:

25/r = 25/(r + 10) + 1/12

Multiplying both sides by 12r(r + 10), we have:

300(r + 10) = 300r + r(r + 10)

300r + 3000 = 300r + r^2 + 10r

r^2 + 10r - 3000 = 0

(r + 60)(r - 50) = 0

r = -60 or r = 50

Since r can't be negative, r = 50 km/hr.

Answer: C

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage