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by MBA.Aspirant » Tue Jun 21, 2011 7:10 pm
1. If a^2 + b^2 + 2ab + 2a + 2b = 4, then what is the value of a^2+b^2?
A. 2
B. 3
C. 4
D. 5
E. 6



7. Given an equation x^2 - x + 1 = 0. Find the number of possible values of x?
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Source: — Problem Solving |

by garima99 » Tue Jun 21, 2011 7:47 pm
MBA.Aspirant wrote:1. If a^2 + b^2 + 2ab + 2a + 2b = 4, then what is the value of a^2+b^2?
A. 2
B. 3
C. 4
D. 5
E. 6



7. Given an equation x^2 - x + 1 = 0. Find the number of possible values of x?
(a+b+1)^2=2^2
so a+b=1 or a+b=-3
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by Frankenstein » Tue Jun 21, 2011 7:51 pm
Hi,
Q1) a^2 + b^2 + 2ab + 2a + 2b = 4. Adding 1 on both sides, we get
a^2 + b^2 + 2ab + 2a + 2b + 1 = 4 + 1
(a+b+1)^2 = 5
(a+b+1) = sqrt5 or -sqrt5
So, a+b = sqrt5 - 1 or -sqrt5 - 1
For different values of a,b we get different values of a^2 + b^2.
Please check the source again. Many questions you have been posting in this section are really not GMAT questions. It is better for you not solve from this source.

Q2) x^2 - x + 1 = 0 => (x - 1/2)^2+3/4 = 0
(x - 1/2)^2 is always greater than or equal to zero. So, (x - 1/2)^2+3/4 >= 3/4
So, it can never be equal to zero.
There are zero possible values of x.
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by Frankenstein » Tue Jun 21, 2011 7:54 pm
garima99 wrote: (a+b+1)^2=2^2
so a+b=1 or a+b=-3
Hi,
There is no '1' on LHS. If you have added it you should also add on RHS. Please check that part.
Cheers!

Things are not what they appear to be... nor are they otherwise
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by MBA.Aspirant » Tue Jun 21, 2011 8:02 pm
Thanks for your reply.

isn't (a+b+1)^2 = a^2 +b^2+1+2ab

that's missing 2a+2b and an extra 1
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by Frankenstein » Tue Jun 21, 2011 8:21 pm
MBA.Aspirant wrote:Thanks for your reply.

isn't (a+b+1)^2 = a^2 +b^2+1+2ab

that's missing 2a+2b and an extra 1
Hi,
(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc +2ca
So, (a+b+1)^2 = a^2 + b^2 + 2ab + 2a + 2b + 1
Cheers!

Things are not what they appear to be... nor are they otherwise
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