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routes and percentages

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Source: — Problem Solving |

by vishubn » Mon Oct 20, 2008 11:51 pm
oopssie :)
i found the misatake !!

i got it ... newys i leave the post open :)

Vishu
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by vcb » Tue Oct 21, 2008 2:23 am
Thats a lot of routes! :))
and its easy to get confused tracing the paths for the Y exit. We could calculate the number of cars from the X exit, the answer would be 100-(Xexits). It definitely is a lot more easier to calculate the number of cars in the X exit.
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A

by suddhasil » Tue Oct 21, 2008 3:45 am
Its A
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by yezz » Tue Oct 21, 2008 4:34 am
75%
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by cramya » Tue Oct 21, 2008 5:10 am
Assume 100 people come in through C

If you calculate the top half (25+12.5) then the bottom half is 50

87.5/100 = A)

Vishu, whats the OA?
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by stop@800 » Tue Oct 21, 2008 5:59 am
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by ab78 » Tue Oct 21, 2008 6:02 am
another take for A.
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by vishubn » Tue Oct 21, 2008 6:46 am
Its A :)

Easy but kinda nice problem isnt it guys ???

thats the reason i left the post open

Vishu
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