Thanks to everybody in advance for replying to this post.
See the attached.
See the attached.
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Gmat Prep - ratio question
Source: Beat The GMAT — Problem Solving |
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sureshbala
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Since the rate of the reaction is directly proprotional to square of A and inversely proportional to B, when B is increased by 100% in order to keep the rate constant the square of A must also increase by 100%.
i.e initially if A = 10, we have A^2 = 100
Now what should be the value of A such that A^2 = 200.
i.e. A = sqrt(200) = 10 x sqrt(2) =14.12 approximately.
Thus initially A = 10 and now it is 14.
So an increase of 40% would keep the rate constant
i.e initially if A = 10, we have A^2 = 100
Now what should be the value of A such that A^2 = 200.
i.e. A = sqrt(200) = 10 x sqrt(2) =14.12 approximately.
Thus initially A = 10 and now it is 14.
So an increase of 40% would keep the rate constant
