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perimeter of a certain isoceles right triangle

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by pappueshwar » Fri Mar 23, 2012 5:52 am
The perimeter of a certain isoceles right triangle is 16 + 16/ sqrt{2}. what is the hypotenuse of the triangle?

A. 8
B. 16
C. 4\sqrt{2}
D. 8\sqrt{2}
E. 16\sqrt{2}

OA IS B unable to understand
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by LalaB » Fri Mar 23, 2012 6:08 am
https://www.beatthegmat.com/the-perimete ... 14645.html

https://www.beatthegmat.com/triangle-iso ... cityevent=

https://www.manhattangmat.com/forums/the ... t1689.html
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by ShrutiN » Fri Mar 30, 2012 3:39 am
Let one non-hypotenuse side of the triangle be 'a'
Second non-hypotenuse side is also 'a' (isoceles)

Hypotenuse= sqrt(a^2+a^2)=a*sqrt(2)

Perimeter=2a+a*sqrt(2)........................................(1)
which in question is given as 16+16/sqrt(2)
This can also be written as 16 + 16*sqrt(2)/2=16+8*sqrt(2)................(2)

Equating (1) and (2)

it is clear that a=8 and hypotenuse which is a*sqrt(2)=8*sqrt(2) or 16/sqrt(2)

Hope that helps!!!
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by Pharo » Sat Mar 31, 2012 11:09 pm
The above are different than the question posted here :)
pappueshwar wrote:The perimeter of a certain isoceles right triangle is 16 + 16/ sqrt{2}. what is the hypotenuse of the triangle?
The answer to this question is E :)
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