himu wrote:Is q > r?
(1) qr = 32
(2) q^2 > r^2
Target question:
Is q > r?
Statement 1: qr = 32
There are several pairs of values that meet this condition. Here are two:
Case a: q = 32 and r = 1, in which case
q is greater then r
Case b: q = -32 and r = -1, in which case
q is not greater then r
Since we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: q^2 > r^2
There are several pairs of values that meet this condition. Here are two:
Case a: q = 32 and r = 1, in which case
q is greater then r
Case b: q = -32 and r = -1, in which case
q is not greater then r
Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined:
There are still several pairs of values that meet the two given conditions. Here are two:
Case a: q = 32 and r = 1, in which case
q is greater then r
Case b: q = -32 and r = -1, in which case
q is not greater then r
Since we still cannot answer the
target question with certainty, the combined statements are NOT SUFFICIENT
Answer =
E
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
