please check the question.. its not making sense.... some symbols are missing somewhere... its that 1/6 and 2/3 or what??

maihuna wrote:In a certain lottery, the probability that a number between 12 and 20, inclusive, is drawn is 1 in 6 . If the probability that a number 12 or larger is drawn is 2 in 3, what is the probability that a number less than or equal to 20 is drawn?

(A) 1/18
(B) 1/6
(C) 1/3
(D) 1/2
(E) 5/6

I fixed the question - please always preview your posts to make sure that they're readable!

This is a simple question to solve once you've broken it down, so let's get to breaking!

If the probability of 12 or larger is 2/3 and the probability of 12-20 is 1/6, then we can set up and solve the following equation:

Prob(12+) = Prob(12-20) + Prob(21+)
2/3 = 1/6 + Prob(21+)
2/3 - 1/6 = Prob(21+)
4/6 - 1/6 = Prob(21+)
3/6 = 1/2 = Prob(21+)

We can now answer the question by setting up and solving one more equation:

Prob(want) = 1 - Prob(don't want)
Prob(less than or equal to 20) = 1 - Prob(greater than 20)
Prob(less than or equal to 20) = 1 - 1/2 = 1/2

choose (D)!