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OG13 PS question, Please help

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OG13 PS question, Please help

by sanaa.rizwan » Mon Apr 01, 2013 3:33 pm
Seed mixture X is 40% ryegrass and 60% bluegrass by weight, seed mixture Y is 25% ryegrass and 75% fescue, If a mixture X & Y contains 30% ryegrass, what percent of the weight of the mixture is X

a.10%
b.33 1/3%
c.40%
d.50%
e.60 2/3%
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by GMATGuruNY » Mon Apr 01, 2013 4:04 pm
I posted a solution in the second half of my post here:

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by Lifetron » Mon Apr 01, 2013 9:58 pm
Typical Alligation problem. Jus use that X method...

40 25
30
5 10

1:2 => Mixture X = 1/3 = 33.3%

Answer B !
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