joyseychow wrote:If x and y are non-zero integers and |x| + |y| = 32, what is xy?
(1) -4x - 12y = 0
(2) |x| - |y| = 16
[spoiler]OA is A. Am I missing something here? Why stmt 1 is sufficient? [/spoiler]
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So, I think the question reduces to:-
If x and y are non-zero integers and |x| + |y| = 32, what is xy?
(1) -4x-12y = 0
(2) |x| (minus) |y| = 16
Soln:-Now for x and y to be non-zero integers we have the following sets
(1,31);(2,30)...........(29,3);(30,2);(31,1) ------ [Total=31]
Taking both the positive and negative signs of x and y,we have 31x4 solns.
Statement 1:It gives x=-3y that means we have y=-8,x=24 and y=8,x=-24.In both the cases,the product xy remains the same.
Statement 2: |x| - |y|=16 gives four solutions , x=+24,y=-8;x=+24,y=+8;x=-24,y=-8;x=-24,y=+8.Over here the product is varying.
Hence , only statement (1) is sufficient for answering the question.
I guess it clears your doubt.
