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of x, y, and z

by sanju09 » Sat Jul 24, 2010 4:13 am
Are the integers x, y, and z consecutive?

1. The arithmetic mean (average) of x, y, and z is y.
2. y - x = z - y.

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by clock60 » Sat Jul 24, 2010 5:42 am
got E here
(1) (x+y+z)/3=y from here x+z=2y. and many versions are possible
y=1, x=1,z=1 not consecutive
y=2,x=1,z=3 consecutive
insufficient
(2)y-x=z-y, 2y=x+z the reasoning the same as for st 1
both insuffiicent
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by selango » Sat Jul 24, 2010 6:16 am
1. The arithmetic mean (average) of x, y, and z is y.
2. y - x = z - y.


Stmt1,

x y z

Median=y

y=(x+y+z)/3

If the numbers are consecutive,mean of numbers is equal to median.

Sufficient.

Stmt2,

y - x = z - y.

2y=x+z

y=(x+z)/2

If the numbers are consecutive, median is equal to average of range.

Sufficient.

Hence D
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by sanju09 » Sat Jul 24, 2010 6:21 am
selango wrote:1. The arithmetic mean (average) of x, y, and z is y.
2. y - x = z - y.


Stmt1,

x y z

Median=y

y=(x+y+z)/3

If the numbers are consecutive,mean of numbers is equal to median.

Sufficient.

Stmt2,

y - x = z - y.

2y=x+z

y=(x+z)/2

If the numbers are consecutive, median is equal to average of range.

Sufficient.

Hence D
This is mere misinterpretation of the correct definitions of few mathematical terminologies.
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by selango » Sat Jul 24, 2010 6:31 am
oops..my mistake..

Got it..its works also for evenly spaced numbers.rt?
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by outreach » Sat Jul 24, 2010 7:33 am
1. The arithmetic mean (average) of x, y, and z is y.

(x+y+z)/3=y
x+z=2y

x z y
1 4 7 no corresponding num
3 4 5 corresponding num

insuff

2. y - x = z - y.
x+z=2y
x z y
1 4 7 no corresponding num
3 4 5 corresponding num

insuff


comb 1 and 2
insuff

sanju09 wrote:Are the integers x, y, and z consecutive?

1. The arithmetic mean (average) of x, y, and z is y.
2. y - x = z - y.

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