BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Interesting DS - Three sets

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 184
Joined: Tue Sep 07, 2010 9:43 amFollowed by: 1 member
Thanked: 6 times
by rahulvsd » Tue Oct 18, 2011 7:56 am
Image

This table lists enrollment in an afterschool program by activity. There are 30 total students enrolled in the entire program. Students may participate in one, two, or three activities. How many students participate in all three activities?

(1) 21 students only participate in one activity.

(2) 6 students participate in both basketball and math.

OA: [/img]A[/img]
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
User avatar
Master | Next Rank: 500 Posts
Posts: 496
Joined: Tue Jun 07, 2011 5:34 amFollowed by: 1 member
Thanked: 38 times

by sl750 » Tue Oct 18, 2011 12:19 pm
a b c represent each of the clubs respectively
ab - represent students in clubs a and b
bc - represent students in clubs b and c
ca - represent students in clubs ca
abc- represent students in all three clubs
30 = 19+12+11 - (ab+bc+ca) - 2abc ---------1

Statement 1
30 = Exactly 1 club + Exactly 2 clubs +Exactly 3 clubs --------2
Exactly 1 club = 21
Exactly 2 clubs = ab+bc+ca
Exactly 3 clubs = abc

12 = ab+bc+ca + 2abc ----- 3
9 = ab+bc+ca + abc ----- 4

Subtract equation 4 from equation 3
3 = abc . Sufficient

Statement 2
ab = 6 . Insufficient
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 105
Joined: Sun Jan 25, 2009 6:55 pmFollowed by: 1 member
Thanked: 2 times

by bpdulog » Fri Oct 21, 2011 12:06 pm
12 = ab+bc+ca + 2abc ----- 3

How did you get this?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 496
Joined: Tue Jun 07, 2011 5:34 amFollowed by: 1 member
Thanked: 38 times

by sl750 » Fri Oct 21, 2011 12:20 pm
Simplify equation 1
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1101
Joined: Fri Jan 28, 2011 7:26 amFollowed by: 13 members
Thanked: 47 times
GMAT Score:640

by HSPA » Fri Nov 11, 2011 10:18 pm
I guess you are well aware of formuala:

(AuBuC) = A+ B +C - AB - BC -CA + ABC ---> mark it equ 1
30 = 19+12+11 -(AB+BC+CA) +ABC

Now option 1 says that we have total of 21 who are exactly in one set only
A only ---- C only ---- B only
(A - AB - CA)+ (C - CA - BC) + (B - BC - BA) + 3ABC = 21 --> mark it 2

solving these 2 you will have the answer.
(hope you understood how 3ABC is added - we removed from A twice the intersections AB,CA, so ABC was added once in each case to make it balance.. thus 3ABC)
bpdulog wrote:12 = ab+bc+ca + 2abc ----- 3

How did you get this?
First take: 640 (50M, 27V) - RC needs 300% improvement
Second take: coming soon..
Regards,
HSPA.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1