stem 1 says (x+y)^2>6
i.e x^2+y^2+2xy>6
you may be tempted here to conclude that then (x+y)^2<6
think of the case now like this
x^2+y^2+2xy>6
then may be x^2+y^2 was equal to 4 and 2xy was equal to 3 so x^2+y^2 <6, even though x^2+y^2+2xy>6
or may be x^2+y^2 was equal to 8 and 2xy was equal to 1 so x^2+y^2 >6 even though x^2+y^2+2xy>6
insufficient
stem 2 is not sufficient as we see
using both stem 1 and 2
x^2+y^2+2xy>6....putting value of xy
x^2+y^2>4
so x^2+y^2 could be equal to 5
or x^2+y^2 could be equal to 10
so insufficient
Is x2 + y2 > 6
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- ayushiiitm
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Thank you.. thats a really nice explanationayushiiitm wrote:stem 1 says (x+y)^2>6
i.e x^2+y^2+2xy>6
you may be tempted here to conclude that then (x+y)^2<6
think of the case now like this
x^2+y^2+2xy>6
then may be x^2+y^2 was equal to 4 and 2xy was equal to 3 so x^2+y^2 <6, even though x^2+y^2+2xy>6
or may be x^2+y^2 was equal to 8 and 2xy was equal to 1 so x^2+y^2 >6 even though x^2+y^2+2xy>6
insufficient
stem 2 is not sufficient as we see
using both stem 1 and 2
x^2+y^2+2xy>6....putting value of xy
x^2+y^2>4
so x^2+y^2 could be equal to 5
or x^2+y^2 could be equal to 10
so insufficient
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swiftwolff
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I find (2)xy=2 sufficient somehow... because there are only limited possibilities for the product of x and y, It could be x=2 y=1, x=1 y=2, x=-2 y=-1, x=-1 y=-2, x=square root of 2 y=square root of 2 (also negative square root of 2). When square all of the set, all of the answer sets will add up to be less than 6. Can anyone comment on this?
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swiftwolff
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- Anurag@Gurome
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(1) (x + y)² > 6 implies x² + y² + 2xy > 6naki009 wrote:Is x^2 + y^2 > 6?
(1) (x + y)^2 > 6
(2) xy = 2
OA : E
I can anyone please explain the answer for this ?
If x² + y² = 5 and 2xy = 3, then x² + y² < 6
If x² + y² = 10 and 2xy = 3, then x² + y² > 6
No definite answer; NOT sufficient.
(2) xy = 2
If x = y = √2, then x² + y² = 4 < 6
If x = 10, y = 1/5, then x² + y² = 100 + 1/25 > 6
No definite answer; NOT sufficient.
Combining (1) and (2), x² + y² + 2xy > 6
x² + y² + 2(2) > 6
x² + y² + 4 > 6
x² + y² > 2
If x² + y² = 5, then x² + y² < 6
If x² + y² = 10 , then x² + y² > 6
No definite answer; NOT sufficient.
The correct answer is E.
Anurag Mairal, Ph.D., MBA
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