GMAT Prep Integers

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 468
Joined: Sat Mar 03, 2007 10:17 pm
Thanked: 5 times

GMAT Prep Integers

by moneyman » Sat May 10, 2008 6:36 am
If k is a positive integer, is k the square of an integer ?

(1) k is divisible by 4

(2) k is divisible by exactly 4 different prime numbers.

Ans E

I chose B
Maxx
Source: — Data Sufficiency |

Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Wed May 07, 2008 7:47 pm
Thanked: 1 times

if you suppose the number = 2*2*3*5*7

by kbm1975 » Sun May 11, 2008 5:00 pm
it satisfys (1),(2) but is not the square of integer.

Legendary Member
Posts: 574
Joined: Sun Jun 01, 2008 8:48 am
Location: Bangalore
Thanked: 28 times

by vishubn » Thu Oct 02, 2008 9:53 pm
any more take on this ! answer is E buit somehow not convinced :(

Vishu

User avatar
Master | Next Rank: 500 Posts
Posts: 316
Joined: Mon Sep 22, 2008 12:04 am
Thanked: 36 times
Followed by:1 members

Re: GMAT Prep Integers

by Morgoth » Thu Oct 02, 2008 10:03 pm
moneyman wrote:If k is a positive integer, is k the square of an integer ?

(1) k is divisible by 4

(2) k is divisible by exactly 4 different prime numbers.

Ans E

I chose B

Statement (1)

k is divisible by 4
k=4=2^2
k=28 not a square of an integer. Insufficient.

Statement (2)

k is divisible by exactly 4 different prime numbers.
k=2*3*5*7 not a square of an integer.
k=2^2*3^2*5^2*7^2 square of an integer. Insufficient.

Combining (1)&(2)

k = 2*2*3*5*7 = divisible by 4, 4 different prime,- not a square of an integer

k = 2^2*3^2*5^2*7^2= divisible by 4, 4 different prime, square of an integer.

Insufficient.

Thus, E.

Hope this helps.

User avatar
Legendary Member
Posts: 871
Joined: Wed Aug 13, 2008 7:48 am
Thanked: 48 times

Re: GMAT Prep Integers

by stop@800 » Thu Oct 02, 2008 10:17 pm
Morgoth wrote:
moneyman wrote:If k is a positive integer, is k the square of an integer ?

(1) k is divisible by 4

(2) k is divisible by exactly 4 different prime numbers.

Ans E

I chose B

Statement (1)

k is divisible by 4
k=4=2^2
k=28 not a square of an integer. Insufficient.

Statement (2)

k is divisible by exactly 4 different prime numbers.
k=2*3*5*7 not a square of an integer.
k=2^2*3^2*5^2*7^2 square of an integer. Insufficient.

Combining (1)&(2)

k = 2*2*3*5*7 = divisible by 4, 4 different prime,- not a square of an integer

k = 2^2*3^2*5^2*7^2= divisible by 4, 4 different prime, square of an integer.

Insufficient.

Thus, E.

Hope this helps.
True, it has to be E

Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Sun Nov 14, 2010 7:04 am

by bohdan01 » Sat Jun 04, 2011 2:33 pm
Statement (1)

k is divisible by 4
k=4=2^2
k=28 not a square of an integer. Insufficient.

Statement (2)

k is divisible by exactly 4 different prime numbers.
k=2*3*5*7 not a square of an integer.
k=2^2*3^2*5^2*7^2 square of an integer. Insufficient.

Combining (1)&(2)

k = 2*2*3*5*7 = divisible by 4, 4 different prime,- not a square of an integer

k = 2^2*3^2*5^2*7^2= divisible by 4, 4 different prime, square of an integer.

Insufficient.

Thus, E.

Hope this helps.
NO doubt about the answer but picking number via trial and error is very time consuming...any other, faster suggestions

User avatar
Legendary Member
Posts: 1309
Joined: Mon Apr 04, 2011 5:34 am
Location: India
Thanked: 310 times
Followed by:123 members
GMAT Score:750

by cans » Sat Jun 04, 2011 7:40 pm
bohdan01 wrote:
Statement (1)

k is divisible by 4
k=4=2^2
k=28 not a square of an integer. Insufficient.

Statement (2)

k is divisible by exactly 4 different prime numbers.
k=2*3*5*7 not a square of an integer.
k=2^2*3^2*5^2*7^2 square of an integer. Insufficient.

Combining (1)&(2)

k = 2*2*3*5*7 = divisible by 4, 4 different prime,- not a square of an integer

k = 2^2*3^2*5^2*7^2= divisible by 4, 4 different prime, square of an integer.

Insufficient.

Thus, E.

Hope this helps.
NO doubt about the answer but picking number via trial and error is very time consuming...any other, faster suggestions
a)k=4*m (m is an integer)
Insufficient. m can be square of an integer or not.
b)k is divisible by exactly 4 different prime numbers. ( to mae is square k should be divisible by square of each prime number.) Insufficient.
a &b) k=4*m and m is product of 3 prime numbers (if they have odd power - not square, if all of them have even, then square) Insufficient
IMO E
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!

Senior | Next Rank: 100 Posts
Posts: 85
Joined: Tue Sep 02, 2008 12:13 am
Thanked: 1 times
GMAT Score:650

by vzzai » Sat Jun 04, 2011 8:44 pm
(2) k is divisible by exactly 4 different prime numbers.

I was stumped by this statement.
I read it as only 4 different primes, without considering powers of primes!
Therefore, I resolved it as 'C' because there would be no square that is a multiple of 4 and divisible by exactly 4 different primes.
Thank you,
Vj

User avatar
Legendary Member
Posts: 1325
Joined: Sun Nov 01, 2009 6:24 am
Thanked: 105 times
Followed by:14 members

by vikram4689 » Sun Jun 05, 2011 4:01 am
A) insufficient, one e.g. is 8
B) insufficient, no=2*3*5*7

A&B no is 2*2*3*5*7 ....not a square

Hence, E
Premise: If you like my post
Conclusion : Press the Thanks Button ;)