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Is x<y?

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Source: — Data Sufficiency |
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by liferocks » Sat May 01, 2010 8:20 pm
Both conditions are not sufficient alone
ex. when x=2 and y=1 x>y but 1/x<1/y

from 2-- either x or y is negative but which one we don't know

combining both ..x is negative and y is positive
hence X<Y--- sufficient

Ans option C
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by harshavardhanc » Sat May 01, 2010 11:27 pm
liferocks wrote:Both conditions are not sufficient alone
ex. when x=2 and y=1 x>y but 1/x<1/y

from 2-- either x or y is negative but which one we don't know

combining both ..x is negative and y is positive
hence X<Y--- sufficient

Ans option C
liferocks,

i think statement 1 is sufficient to tell us that x will never be less than y, as their reciprocal follow the less than relation.

in other words, if 1/x < 1/y, X will be greater than Y.

please correct me if I'm wrong.

IMO A
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Harsha
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by liferocks » Sun May 02, 2010 5:51 am
@harshavardhanc
if 1/x<1/y
we get y<x if xy is positive
and y>x..if xy is negative

is this not correct?
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by harshavardhanc » Sun May 02, 2010 9:36 pm
liferocks wrote:@harshavardhanc
if 1/x<1/y
we get y<x if xy is positive
and y>x..if xy is negative

is this not correct?
i see.....i missed that....thanks mate!

agree with your answer now. :)
Regards,
Harsha
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by gmatmachoman » Mon May 03, 2010 3:33 am
harshavardhanc wrote:
liferocks wrote:@harshavardhanc
if 1/x<1/y
we get y<x if xy is positive
and y>x..if xy is negative

is this not correct?
i see.....i missed that....thanks mate!

agree with your answer now. :)
@harsha bhai,

Yesterday i was about to "pinpoint" that error..but i was so sleepy in that afternoon..so dozed off..Now LR hasdone the job.. Now i got that y u said we need to work on "silly mistakes" sometime back...

There is also a nice DS posted by colakumarfanta( cool name for teh Summers) CHk that out
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