BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

ds ques

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times
by vivek.kapoor83 » Sat Oct 04, 2008 4:32 am
If k, m, and t are positive integers and + = , do t and 12 have a common factor greater than 1 ?
(1) k is a multiple of 3.
(2) m is a multiple of 3.



Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-mails, and talking on the phone. If she did no two of these three activities at the same time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was 90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was 60 percent of the total amount of time that she spent responding to E-mails and talking on the phone.






Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ?

A. 1/6
B. 1/5
C. 1/3
D. 2/5
E. 2/3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Sat Oct 04, 2008 10:34 am
Actually there are 3 ques...need the ans of all 3...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member
Thanked: 27 times
GMAT Score:660(

by 4meonly » Sat Oct 04, 2008 12:30 pm
Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-mails, and talking on the phone. If she did no two of these three activities at the same time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was 90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was 60 percent of the total amount of time that she spent responding to E-mails and talking on the phone.

I think C


training class - T
responding to E-mails - R,
and talking on the phone - P
Total 240 min

(1)
training class - T........................0,9x
responding to E-mails - R............x
and talking on the phone - P........240-1,9x
Total 240 min
P=?
INSUFF

(2)
training class - T........................
responding to E-mails - R............
and talking on the phone - P........
Total 240 min

T=0,6(E+P)
E+P=y
0,6(E+P) + E+P= 0,6y+y=240
1,6y=240
y=150, T=90
P=?
INSUFF

(1)(2)
240-0,9x=150
x=100
1,9x=190
P=50
SUFF

C

OA?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member
Thanked: 27 times
GMAT Score:660(

by 4meonly » Sat Oct 04, 2008 12:49 pm
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ?

A. 1/6
B. 1/5
C. 1/3
D. 2/5
E. 2/3

I am between C and D...
Post OA please
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 316
Joined: Mon Sep 22, 2008 12:04 amFollowed by: 1 member
Thanked: 36 times

Re: ds ques

by Morgoth » Sat Oct 04, 2008 2:42 pm
vivek.kapoor83 wrote:If k, m, and t are positive integers and + = , do t and 12 have a common factor greater than 1 ?
(1) k is a multiple of 3.
(2) m is a multiple of 3.
"+ = " what does this mean.

Something is missing for sure.


Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-mails, and talking on the phone. If she did no two of these three activities at the same time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was 90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was 60 percent of the total amount of time that she spent responding to E-mails and talking on the phone.

total minutes = 240
class, e-mails, phone
phone=?

Statement (1)
C = .90 E
Insufficient.

Statement (2)
C = .60(E+P)
Insufficient.

Combining (1) & (2)
We solve P, Since we know C+E+P = 240
3 equations, 3 variables.

Thus, C.




Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ?

A. 1/6
B. 1/5
C. 1/3
D. 2/5
E. 2/3

sum of 8

6+2
2+6
4+4
3+5
5+3

total cases = 5
favorable cases = 2

probability = 2/5.

Thus, D.

OAs?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 29
Joined: Fri Jul 04, 2008 6:57 pm
Thanked: 1 times

by kv_ajay » Tue Oct 21, 2008 8:37 am
OA's are in order:
1) A
2) C
3) D
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Tue Oct 21, 2008 5:22 pm
Quick question

For problem 3Like 4 meonly i was torn between 1/3 and 2/5

Morgoth,
sum of 8

6+2
2+6
4+4
3+5
5+3


Why dont we consider another 4,4 i.e first draw second draw and second draw first draw?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member
Thanked: 27 times
GMAT Score:660(

by 4meonly » Wed Oct 22, 2008 8:08 am
I think because we cannot distinguish 2 different cases between 4+4 and 4+4. They are the same, thats why there should be 5 different outcomes with 2 desirable outcomes.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 10
Joined: Fri Jul 18, 2008 11:15 pm

Re: ds ques

by drpawan » Wed Oct 22, 2008 8:32 am
vivek.kapoor83 wrote:If k, m, and t are positive integers and + = , do t and 12 have a common factor greater than 1 ?
(1) k is a multiple of 3.
(2) m is a multiple of 3.
---> Didnt get ur question. Would you again post this please?

vivek.kapoor83 wrote:Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-mails, and talking on the phone. If she did no two of these three activities at the same time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was 90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was 60 percent of the total amount of time that she spent responding to E-mails and talking on the phone.

--> Ans is C(Using both the statements) and the explanation is already given by the friends.

vivek.kapoor83 wrote:Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ?

A. 1/6
B. 1/5
C. 1/3
D. 2/5
E. 2/3
Ans is 2/5
total no of possible outcomes = (2,6)(6,2)(3,5)(5,3)(4,4) = 5
total no of favorable outcomes = (3,5)(5,3) = 2
So, 2/5
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 882
Joined: Fri Feb 20, 2009 2:57 pmFollowed by: 1 member
Thanked: 15 times
GMAT Score:690

by crackgmat007 » Thu Nov 05, 2009 1:07 pm
vivek.kapoor83 wrote:
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ?

A. 1/6
B. 1/5
C. 1/3
D. 2/5
E. 2/3


Ans is 2/5
total no of possible outcomes = (2,6)(6,2)(3,5)(5,3)(4,4) = 5
total no of favorable outcomes = (3,5)(5,3) = 2
So, 2/5
Why total possible outcomes is 5. Shouldnt it be 6, coz 4,4 is not counted twice. Or should we not count it twice? Since, order doesnt matter, it looks like we need to. Is this reasoning wrong?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1