bml1105 wrote:What is the value of (x^2 - y^2)?
(1) x + y = 2x
(2) x - y = 0
x² - y² = (x+y)(x-y).
Question stem, rephrased:
What is the value of (x+y)(x-y)?
Statement 1: x+y = 2x
Subtracting x from both sides, we get:
y = x
0 = x-y.
Thus, (x+y)(x-y) = (x+y)(0) = 0.
SUFFICIENT.
Statement 2: x-y = 0
Thus, (x+y)(x-y) = (x+y)(0) = 0.
SUFFICIENT.
The correct answer is
D.
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