-
AleksandrM
- Legendary Member
- Posts: 566
- Location: Philadelphia
- Thanked: 31 times
- GMAT Score:640
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Featured Course
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
Inequalities - GMATPrep
Source: Beat The GMAT — Data Sufficiency |
Answer should be A.
1) 2x-3y=-2= -ve. Since, x^2=+ve => 2x-3y <x^2 Sufficient
2) x>2; y>0 =>2x-3y>4 i.e. 2x-3y = 5,6,7....
Also, x>2 =>x^2>4 i.e. x^2 = 5,6,7....
Now if 2x-3y = 5 and x^2 =6 then Left side < Right side.
If 2x-3y = 6 and x^2 = 5 then LS > RS. Not sufficient.
1) 2x-3y=-2= -ve. Since, x^2=+ve => 2x-3y <x^2 Sufficient
2) x>2; y>0 =>2x-3y>4 i.e. 2x-3y = 5,6,7....
Also, x>2 =>x^2>4 i.e. x^2 = 5,6,7....
Now if 2x-3y = 5 and x^2 =6 then Left side < Right side.
If 2x-3y = 6 and x^2 = 5 then LS > RS. Not sufficient.
-
AleksandrM
- Legendary Member
- Posts: 566
- Location: Philadelphia
- Thanked: 31 times
- GMAT Score:640
The answer is D. However, I would like to know more than just the correct answer, which I already knew. I want to know WHY the answer is D and HOW you would get there. Thanks. 
(1) Sufficient because:
=> x^2 is always +ve.
=> given 2x - 3y = -2, which is -ve.
=> Since a -ve num < +ve num, we can say with certainty that 2x - 3y < x^2.
(2) Sufficient because:
=> Given x > 2, y > 0
=> Note that for all n > 2, 2n < n^2 ( you can plug numbers in)
=> Also given that y > 0, so 2n - 3y further reduces the Left hand side.
Therefore, Ans is D
=> x^2 is always +ve.
=> given 2x - 3y = -2, which is -ve.
=> Since a -ve num < +ve num, we can say with certainty that 2x - 3y < x^2.
(2) Sufficient because:
=> Given x > 2, y > 0
=> Note that for all n > 2, 2n < n^2 ( you can plug numbers in)
=> Also given that y > 0, so 2n - 3y further reduces the Left hand side.
Therefore, Ans is D
AleksandrM wrote:The answer is D. However, I would like to know more than just the correct answer, which I already knew. I want to know WHY the answer is D and HOW you would get there. Thanks.
