Remainder

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Remainder

by harsh.champ » Mon Feb 08, 2010 4:51 am
What is the remainder when P2 is divided by 12, where 'P' is a prime number?
A: P is of the form 4k + 3, where 'k' is a positive integer.
B: P is of the form 2k - 1, where 'k' is an integer greater than 1.

The OA is A.
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by shashank.ism » Mon Feb 08, 2010 5:06 am
harsh.champ wrote:What is the remainder when P2 is divided by 12, where 'P' is a prime number?
A: P is of the form 4k + 3, where 'k' is a positive integer.
B: P is of the form 2k - 1, where 'k' is an integer greater than 1.

The OA is A.
A sufficient P can be 7, 11,19,23.... -- all have different remainder ....... 7 & 11, --- not sufficient
B unsufficient all odd nos. which are prime so remiander may be 5,7,11,1,3, ---not sufficient...
A and B gives same nos.as A

so combined is also insufficient
ANSE


Harsh will u please explain how ans is A
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by sanju09 » Mon Feb 08, 2010 5:12 am
harsh.champ wrote:What is the remainder when P2 is divided by 12, where 'P' is a prime number?
A: P is of the form 4k + 3, where 'k' is a positive integer.
B: P is of the form 2k - 1, where 'k' is an integer greater than 1.

The OA is A.
With P2, do you mean P^2?
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by harsh.champ » Mon Feb 08, 2010 5:17 am
sanju09 wrote:
harsh.champ wrote:What is the remainder when P2 is divided by 12, where 'P' is a prime number?
A: P is of the form 4k + 3, where 'k' is a positive integer.
B: P is of the form 2k - 1, where 'k' is an integer greater than 1.

The OA is A.
With P2, do you mean P^2?
Yeah sanju I forgot the "^" sign over there. It would be P^2.

So,the question will be:-

What is the remainder when P2 is divided by 12, where 'P' is a prime number?
A: P is of the form 4k + 3, where 'k' is a positive integer.
B: P is of the form 2k - 1, where 'k' is an integer greater than 1.



Just check now if you are getting the correct answer.
Sorry for the inconvenience.
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



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by sanju09 » Mon Feb 08, 2010 5:33 am
harsh.champ wrote:
sanju09 wrote:
harsh.champ wrote:What is the remainder when P2 is divided by 12, where 'P' is a prime number?
A: P is of the form 4k + 3, where 'k' is a positive integer.
B: P is of the form 2k - 1, where 'k' is an integer greater than 1.

The OA is A.
With P2, do you mean P^2?
Yeah sanju I forgot the "^" sign over there. It would be P^2.

So,the question will be:-

What is the remainder when P2 is divided by 12, where 'P' is a prime number?
A: P is of the form 4k + 3, where 'k' is a positive integer.
B: P is of the form 2k - 1, where 'k' is an integer greater than 1.



Just check now if you are getting the correct answer.
Sorry for the inconvenience.
alright

(1) If P = 4 k + 3 for some positive integer k, then P^2 = 16 k^2 + 24 k + 9. Now note that when P is prime, 16 k^2 leaves a remainder of 4, 24 k leaves 0 remainder, and 9 leaves 9 as remainder, when 16 k^2 + 24 k + 9 is divided by 12. Hence, when (4 + 0 + 9) or 13 is divided by 12, the remainder is 1. Sufficient

(2) If P = 2 k - 1 for some positive integer k, greater than 1, then P^2 = 4 k^2 - 4 k + 1. No fix remainders to the parts of 4 k^2 - 4 k + 1 when divided by 12. Insufficient

[spoiler]A[/spoiler]
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