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italian7745
- Master | Next Rank: 500 Posts
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IMO C
statement1) m-3z>0 => m>3z not suff.
s2) 4z-m<0=>m>4z => not suff
again s2) can be written as m-4z>0
now sub 1 and 2
m-3z-m+4z>0
z>0
since m-3z>0 and z>0=>m>0
hence M+Z>0
using bth suff.
Hence C












