manihar.sidharth wrote:At a holiday store, the average price of the German nutcrackers is $225, and the average price of all nutcrackers is $205. What is the average price of the non-German nutcrackers?
(1) The combined price of all the nutcrackers in the store is $2,050.
(2) Sixty percent of the nutcrackers in the store are German.
Statement 1: The combined price of all the nutcrackers in the store is $2,050.
Thus, the total number of nutcrackers = sum/average = 2050/205 = 10.
Case 1:
It's possible that the number of German nutcrackers = 2, with a total cost of 2*225 = 450.
Here, there are 8 non-German nutcrackers, with an average cost of (2050-450)/8 = 200.
Case 2:
It's possible that the number of German nutcrackers = 6, with a total cost of 6*225 = 1350.
In this case, there are 4 non-German nutcrackers, with an average cost of (2050-1350)/4 = 175.
Since the average cost of the non-German nutcrackers can be different values, iNSUFFICIENT.
Statement 2: Sixty percent of the nutcrackers in the store are German.
This is the ratio used in Case 2 above:
Of every 10 nutcrackers (with a total cost of 2050), 6 are German (with a total cost of 1350), with the result that the average cost of the 4 non-German nutcrackers = 175.
SUFFICIENT.
The correct answer is
B.
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