If x and y are positive even numbers and have a sum of 36, how many pairs of x and y that can let x>y are possible?
X + Y = 36 where x and y are both even and positive. also x > y
36/2 = 18 so the largest value of x can be 20 (X can't be 18 as then y must also be 18 and condition of x > y is violated). and x should be less than 36 as both x and Y must be positive. (Thanks for pointing this out)
so x can be any even number from 18 to 34 and y can be the complement that together adds to give 36
How many even numbers between 20 and 34 inclusive?
[(34 - 20) / 2] + 1 = 8 possible combinations of X and Y possible
