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Help with this one - Mean vs. Median

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Help with this one - Mean vs. Median

by thamudis » Fri Feb 24, 2012 9:44 am
Set A and B has equal number of numbers. Is median in A smaller than mean in B?
a) in A, all numbers are consecutive even numbers. in B, all numbers are consecutive odd numbers
b) sum of numbers in A is greater than sum of numbers in B

Thanks!![/spoiler]
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Source: — Data Sufficiency |
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by pemdas » Fri Feb 24, 2012 10:54 am
thamudis wrote:Set A and B has equal number of numbers. Is median in A smaller than mean in B?
a) in A, all numbers are consecutive even numbers. in B, all numbers are consecutive odd numbers
b) sum of numbers in A is greater than sum of numbers in B

Thanks!![/spoiler]
sequence of consecutive numbers returns mean=median, hence in st(1) mean=median for both sets, but we don't know actual numbers, hence Not Sufficient
st(2) since we have equal number of numbers in A and B, the given condition Sum(A)/n>Sum(B)/n implies that set A's mean > set B's mean, but we don't know about the median. Not Sufficient.

combining should be Sufficient, as mean=median and mean of set A > mean of set B.

c
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