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PS - Probability - 1 - either or

by karthikpandian19 » Tue Jul 24, 2012 5:07 am
Anthony is baking pies for 12 of his friends, including Valentino. Anthony chooses one of the 12 pies at random to fill with blackberries. He chooses one of the remaining 11 pies at random to fill with cherries. He then chooses one of the remaining 10 at random to fill with apples. All the other pies will be filled with pumpkin. What is the probability that Valentino's pie will be either the cherry pie or the apple pie?


(A) 1/120

(B) 1/110

(C) 1/12

(D) 1/10

(E) 1/6
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by eagleeye » Tue Jul 24, 2012 5:14 am
karthikpandian19 wrote:Anthony is baking pies for 12 of his friends, including Valentino. Anthony chooses one of the 12 pies at random to fill with blackberries. He chooses one of the remaining 11 pies at random to fill with cherries. He then chooses one of the remaining 10 at random to fill with apples. All the other pies will be filled with pumpkin. What is the probability that Valentino's pie will be either the cherry pie or the apple pie?


(A) 1/120

(B) 1/110

(C) 1/12

(D) 1/10

(E) 1/6
Required probability = (apple or cherry) / (all choices) = (2 choices)/(12 choices) = 2/12 =1/6.

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E is correct
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by karthikpandian19 » Tue Oct 09, 2012 5:56 am
The question seems to be long compared to the solution....hmmm

OA is E
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by Brent@GMATPrepNow » Tue Oct 09, 2012 7:22 am
karthikpandian19 wrote:The question seems to be long compared to the solution....hmmm
Agreed!

It could be reworded as, "Anthony has 1 blackberry pie, 1 cherry pie, 1 apple pie and 9 pumpkin pies. If he randomly selects a pie for Valentino, what is the probability that Valentino's pie will be either cherry or apple?"

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