Company A has a total of n employees, where n is an
odd integer, and no two employees have the same annual
salary. The annual salaries of the n employees are listed
in increasing order, and the 16th salary in the list is the
median of the annual salaries. If the sum of the annual
salaries of Company A’s employees is $942,400, what
is the average (arithmetic mean) of the annual salaries
of Company A’s employees?

A.$29,450
B.$30,400
C.$32,500
D.$47,120
E.$58,900

[spoiler]IMO=> $34,000. bUT OA-B![/spoiler]

total number of employees = 31
so mean = $942,400/31

Where am I wrong?