product of integers from 1 to 8 can be written as
8*7*6*5*4*3*2*1=2^3*7*(3*2 )*5*2^2*2*1=2^7*3^2*5^1*7^1equating with 2^k*3^m*5^j*7^p
gives k=7;m=2;j=1and p=1 adding ans is 11
hth
It does not matter how many times you get knocked down , but how many times you get up