smohsin wrote:from a bag containing 12 identical blue balls, y identical yellow balls and no other balls, one ball will be removed at random. If the probability is less than 2/5 that the removed ball will be blue, what is the least number of yellow balls that must be in the bag?
Ans: 17, 18, 19, 20, 21
Thanks so much for the help.
The probability of Blue Ball <2/5.
To solve this question, let's say that the probability of drawing the blue ball is 2/5. Then, from the question stem you know that there are 12 blue balls. So, if 2 of numerator denotes 12 blue balls, 5 in the denominator denotes 30 balls in total and thus 18 yellow balls (Total 30 = 12 Blue + 18 Yellow).
Since we want to find the least no of yellow balls so that the probability has to be <2/5, you only have to increase the denominator (in essence, number of yellow balls). So, the least number of yellow balls have to be 18+1= 19 balls.
