First you select a base, that can be done in 2 ways
Then you select 4 toppings out of 5, which can be done in 5C4 = 5 ways
Then you select regular, or extra cheese, which can be done in 2 ways
Total options = 2x2x5 = 20
Combinatronics2, MGMAT
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Number of choices of crust = 2 (deep dish or thin).rb90 wrote:
The OA is [spoiler]20. I am getting 10 through 2C1*5C4. [/spoiler]
Please explain where i am going wrong.
Thanks in advance guys.
Number of ways to choose 4 toppings from 5 choices = 5C4 = 5.
Number of choices of cheesy goodness = 2 (extra cheese or regular).
Multiplying, we get 2*5*2 = 20 possible pizzas.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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