rb90 wrote:
The OA is [spoiler]20. I am getting 10 through 2C1*5C4. [/spoiler]
Please explain where i am going wrong.
Thanks in advance guys.
Number of choices of crust = 2 (deep dish or thin).
Number of ways to choose 4 toppings from 5 choices = 5C4 = 5.
Number of choices of cheesy goodness = 2 (extra cheese or regular).
Multiplying, we get 2*5*2 = 20 possible pizzas.
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