BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Strange Venn diagrams question

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Sun Aug 22, 2010 3:23 am

Strange Venn diagrams question

by MarcoRome » Sun Aug 22, 2010 3:40 am
I found this strange question that I understand as a strange type of questions to be solved with Venn diagrams. I am not sure what is the solution:

Judy, Andrew and Marta did a race 48 times. Half of the time Judy was the last. 1/8 times Andrew arrived before Marta and 1/6 of the times Marta arrived before Andrew. How many times did Judy have to arrive first at least?
Top
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 659
Joined: Mon Dec 14, 2009 8:12 am
Thanked: 32 times
Followed by:3 members

by Gurpinder » Sun Aug 22, 2010 7:41 am
This is not a venn diagram question.

First of all, I would say this is not even a proper GMAT question.

But this is a Rate, Time, Distance problem.
"Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress."
- Alfred A. Montapert, Philosopher.
Top
Newbie | Next Rank: 10 Posts
Posts: 7
Joined: Fri Jun 08, 2007 3:29 pm

by srajan » Sun Aug 22, 2010 11:01 pm
Here is my solution:

J came last: 24 times.
Therefore, A and M came 1st or 2nd or draw 24 times.
A arrived before M 1/8 times: 48/8 = 6
M arrived before A 1/6 times: 48/6 = 8
total different ways when they don't have draw = 8+6 =14
Rest of the time they must have draw. i.e. draw = 48-14 = 34

Now we need to find minimum no. of times when J has to come first.
We can find this if we maximize the no. when J cannot become 1st.
This can happen if he comes 2nd, i.e. between A and M.
It can happen maximum of 14 times. (This can happen when A and M have a draw all the times when J came last)
Therefore, J can come first at least 10 times.
Top
Post new topic Post Reply
• Page 1 of 1