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Sweet Problem

by eaakbari » Mon Nov 05, 2012 11:44 am
Enjoy...

A sweetseller has 420 Dark chocolates and 130 Milk chocolates. She wants to
stack them in such a way that each stack has the same number, and they take up the
least area of the tray. What is the number of that can be placed in each stack for this
purpose?
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by pemdas » Mon Nov 05, 2012 2:19 pm
eaakbari wrote:Enjoy...

A sweetseller has 420 Dark chocolates and 130 Milk chocolates. She wants to
stack them in such a way that each stack has the same number, and they take up the
least area of the tray. What is the number of that can be placed in each stack for this
purpose?
420=2*2*3*5*7
130=2*5*13
420/x=130/y and x should be 2*3*7, whereas y=13
420/(2*3*7)=130/13

There should be 42 Dark chocolates and 13 Milk chocolates placed (stacked), total makes 55 pieces of sweets.
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