The o/p of a factory was increased by 10% to keep up with the rising demand.To meet the holiday rush this new o/p was again increased by 20%. By approxmately what percentage the o/p now have to be reduced to restore to the original o/p
I always get this qn wrong ! Please help.
My method.
Initial O/p =x
After first increment o/p = 110/100 * x = 1.1x
After second increment o/p = 1.1 X * 120/100 = 1.32x
Increment is = 0.32x
Now the o/p must be reduced from 1.32 x to x right?
The answer is 24 % I cant seem to reach till there..
I always get this qn wrong ! Please help.
My method.
Initial O/p =x
After first increment o/p = 110/100 * x = 1.1x
After second increment o/p = 1.1 X * 120/100 = 1.32x
Increment is = 0.32x
Now the o/p must be reduced from 1.32 x to x right?
The answer is 24 % I cant seem to reach till there..
Devi!
