Speeding Tickets - Percentages problem

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 44
Joined: Fri Apr 20, 2012 1:02 pm

Speeding Tickets - Percentages problem

by justharsha » Sun Nov 24, 2013 5:32 pm
On a certain road 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?
(A) 10 1/2%
(B) 12 1/2%
(C) 15%
(D) 22%
(E) 30%

[spoiler]OA: B[/spoiler]
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Sun Nov 24, 2013 5:43 pm
justharsha wrote:On a certain road 10 percent of the motorists exceed the posted speed limit and receive speeding tickets, but 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?
(A) 10 1/2%
(B) 12 1/2%
(C) 15%
(D) 22%
(E) 30%

[spoiler]OA: B[/spoiler]
We can use the Double Matrix Method to solve this question.

This technique can be used for most questions featuring a population in which each member has two characteristics associated with it.

Here, we have a population of motorists, and the two characteristics are:
- speeder (S) or non-speeder (~S)
- get ticket (T) or not get ticket (~T)

Aside: To learn more about the Double Matrix Method, watch our free video: https://www.gmatprepnow.com/module/gmat- ... ems?id=919

Since this question concerns percents (instead of actual values), let's assign a "nice" value to the total number of motorists in this population. Let's say there are 100 motorists.

So, to begin, our matrix looks like this.
Image

10 percent of the motorists exceed the posted speed limit and receive speeding tickets
The top left box is for motorists who speed and receive speeding tickets. So, 10% of the entire population will be in this box.
Image

20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets.
The motorists referred to here are those who go in the top right box. Unfortunately, we don't know the total number of speeders, so we can't find 20% of that value.
So, let's let x = the total number of speeders.
Image

Now we can deal with this: 20 percent of the motorists who exceed the posted speed limit do not receive speeding tickets.
In other words, 20% of x will go in the top right box.
Image

At this point, we know that the sum of the top 2 boxes is x.
So, we can write: 10 + 0.2x = x (now solve)
Arrange: 10 = 0.8x
Divide: 10/0.8 = x
12.5 = x

Since x represents the total number of speeders, we know that 12.5 out of 100 motorists speed.
In other words, [spoiler]12.5%[/spoiler] of motorists speed.
Answer: B

---------------------------------------
Here are some additional practice questions that can be solved using the Double Matrix Method:
- https://www.beatthegmat.com/mba/2011/05/ ... question-1
- https://www.beatthegmat.com/mba/2011/05/ ... question-2
- https://www.beatthegmat.com/mba/2011/05/ ... question-3
- https://www.beatthegmat.com/ds-quest-t187706.html
- https://www.beatthegmat.com/overlapping- ... 83320.html
- https://www.beatthegmat.com/finance-majo ... 67425.html
- https://www.beatthegmat.com/ds-french-ja ... 22297.html

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pm
Location: Palo Alto, CA
Thanked: 2867 times
Followed by:511 members
GMAT Score:800

by [email protected] » Sun Nov 24, 2013 6:28 pm
Hi justharsha,

Brent has shown you a particular way to organize your information, which you might find helpful on these types of questions.

Whether you put your information into a table or not, this question is ultimately testing your ability to notice that the given information is (first) about the overall group, then (second) about a sub-group within the overall group.

First piece: 10% of motorists exceed the speed limit and receive tickets.

If we say there are 100 motorists, then we can break them into groups:

Speed and Got Ticket
Speed and Didn't
Didn't speed

With 100 total motorists, we know that 10 of them exceeded the speed limit and received tickets:

Total: 100
Speed and Got Ticket = 10
Speed and Didn't = ?
Didn't speed = ?

Second piece: 20% of the motorists WHO EXCEEDED THE SPEED LIMIT did NOT receive tickets.

This is NOT 20% of the 100, it's 20% of those who EXCEEDED THE SPEED LIMIT. Let's call THAT sub-group X:

X = Those who got a ticket + those who didn't

So, X = 10 + .2X

Now, solve for X
.8X = 10
X = 12.5

Final Answer: B

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Mon Nov 25, 2013 5:29 am
on a certain road 10% of the mototorist exceed the posted limit and receive speeding tickets, but 20% of the motorists who exceed the posted speedlimit do not receive speeding ticket. What percent of the motorists on the road exceed the posted speed limit?
A) 10.5%
B) 12.5%
C) 15%
D) 22%
E) 30%
Let motorists who exceed the speed limit = 10.
Motorists who don't receive a ticket = .2*10 = 2.
Thus, motorists who receive a ticket = 10-2 = 8.
Since these 8 motorists who exceed the speed limit and receive a ticket are 10% of the total, total = 80. (8 is 10% of 80.)
Thus:
(exceed the speed limit)/(total) = 10/80 = 12.5%.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

Senior | Next Rank: 100 Posts
Posts: 44
Joined: Fri Apr 20, 2012 1:02 pm

by justharsha » Mon Nov 25, 2013 10:20 am
Thanks Brent, Rich and GMATGuru!
Much appreciated.