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by dunkin77 » Wed Apr 04, 2007 11:24 am
Hi,

My answer was B) by... 0.5*0.9=0.54+0.05=0.59 but the corect answer was A) - can anyone help please?


Of a group of people surveyed in a political poll, 60 percent said that they would vote for candidate R. Of those who said they would vote for R. 90 percent actually voted for R. and of those who did not say that they would vote for R. 5 percent actually voted for R. What percent of the group voted for R?
(A) 56% (B) 59% (C) 62%
(D) 65% (E) 74%
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Re: 500 PS

by gabriel » Wed Apr 04, 2007 12:50 pm
dunkin77 wrote:Hi,

My answer was B) by... 0.5*0.9=0.54+0.05=0.59 but the corect answer was A) - can anyone help please?


Of a group of people surveyed in a political poll, 60 percent said that they would vote for candidate R. Of those who said they would vote for R. 90 percent actually voted for R. and of those who did not say that they would vote for R. 5 percent actually voted for R. What percent of the group voted for R?
(A) 56% (B) 59% (C) 62%
(D) 65% (E) 74%

5 % of people who did vote for R inspite of saying no wuld equal to =0.4*0.05 = 0.02

so ur answer is 0.6*0.9+0.02=0.56 ...A
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by dunkin77 » Wed Apr 04, 2007 1:20 pm
ohh - I see - thank yoU!
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by BTGmoderatorRO » Sat Nov 04, 2017 11:23 pm
Let the total number of people that took the survey be n. Also let x and y represent the total number of people who said they would vote for candidate R and those who didn't say they will vote for R respectively.
from the question,
x=60% of n
i.e x=0.6n and
y=(100-60)% of n = 40% of n
i.e y=0.4n
Now, the number of people who actually voted for R is = 90% of x + 5% of y
=0.9x + 0.05y
=0.9(0.6n) + 0.05(0.4n)
=0.54n + 0.02n
=0.56n
= $$\frac{56}{100}n$$
$$i.e\ 56\%\ of\ n$$
the correct answer is A
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by Matt@VeritasPrep » Thu Nov 09, 2017 7:29 pm
(90% of 60) + (5% of 40) =>

.9 * 60 + .05 * 40 =>

54 + 2 =>

56
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by Scott@TargetTestPrep » Tue Dec 17, 2019 7:31 pm
dunkin77 wrote:Hi,

My answer was B) by... 0.5*0.9=0.54+0.05=0.59 but the corect answer was A) - can anyone help please?


Of a group of people surveyed in a political poll, 60 percent said that they would vote for candidate R. Of those who said they would vote for R. 90 percent actually voted for R. and of those who did not say that they would vote for R. 5 percent actually voted for R. What percent of the group voted for R?
(A) 56% (B) 59% (C) 62%
(D) 65% (E) 74%
We can let the number of people in the group be 200. So 0.6 x 200 = 120 said that they would vote for candidate R, and 200 - 120 = 80 said that they would not. Of the 120 people who said that they would vote for candidate R, 0.9 x 120 = 108 actually did vote for R. Of the 80 people who said that they would not, 0.05 x 80 = 4 actually did vote for R. Therefore, the percent of the people who voted for R is (108 + 4)/200 = 112/200 = 56/100 = 56%.

Answer: A

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