Question stem tells us "COMBINED"
So:
Defected/Total# = 2+5+6+4/(5+12+18+16)x1000 = 17 / 51000 = 1/3000
So there will be one defected chip per 3000 chips
Since we have 60,000 ---> 20
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Computer chip
Source: Beat The GMAT — Problem Solving |
combining s1 s2 s3 s4...total defective chips =17
total chips -51000
ratio - 1/3000
So, if out of
3000 chips 1 is defective
out of 60000 = 60,000/3,000 = 20
total chips -51000
ratio - 1/3000
So, if out of
3000 chips 1 is defective
out of 60000 = 60,000/3,000 = 20
