OA - E
just draw a circle with the center at 0,0... with a radius of 1 the circle will touch (0,1) (1,0) (0,-1) & (-1,0)
Statement (1) tells you that line K (and i'm pretty sure that yes you imagine it's infinite because it would be called line segment k something not line k) has an x-intercept greater than 1... on your diagram this would be to the right of the point (1,0) you have the circle touching... since you have no idea how far right this point is, it could be at (5000,0) or (2,0) and you have no idea what the slope is, it could be a vertical line like x=5000 or x=2 and never touch the circle, or a regular positive or negative slope. Not sufficient
Statement (2) tells you that the slope of line k is -1/10... this tells you absolutley nothing about the placement of the line in relation of the circle... not sufficient
Together imagine the two examples I gave for possible places of line k on the x-axis... If line K's x-intercept was at (2,0) with a slope of -1/10 it would run right into the circle as it is 1 unit away and hit the y-axis at (0,1/5) (in the circle)... now imagine the line K hits the x-axis at (5000,0) all the way to the right of the circle with a slope of -1/10 it would run all the way back to the y-axis and touch it at (0,500) way above the circle...
therefore the answer is E
