BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

remainder when k is divided by j

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Master | Next Rank: 500 Posts
Posts: 117
Joined: Wed Dec 30, 2009 1:57 pmFollowed by: 1 member
Location: India
Thanked: 4 times
by abhi332 » Wed Feb 24, 2010 12:20 pm
If j and k are positive integers where k > j, what is the value of the remainder when k is divided by j?

(1) There exists a positive integer m such that k = jm + 5.

(2) j > 5
What you think, you become.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
User avatar
Master | Next Rank: 500 Posts
Posts: 102
Joined: Sat Feb 20, 2010 5:38 am
Location: IIM Ahmedabad
Thanked: 10 times

by firdaus117 » Wed Feb 24, 2010 12:51 pm
Condition 1
k%j=(jm+5)%j=5%j=0 to 5 depending on value of j.Insufficient
Condition 2
j > 5 Insuff
Combining 1 and 2,
5%j=5 Sufficient
Option C
n.b. a%b means the remainder when a is divided by b.
Last edited by firdaus117 on Wed Feb 24, 2010 12:53 pm, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 184
Joined: Sat Apr 14, 2007 9:23 am
Location: Madison, WI
Thanked: 17 times

by ldoolitt » Wed Feb 24, 2010 12:51 pm
abhi332 wrote:If j and k are positive integers where k > j, what is the value of the remainder when k is divided by j?

(1) There exists a positive integer m such that k = jm + 5.

(2) j > 5
Right off the bat you can see that (2) itself is not sufficient. Lets say j = 6, which satisfies (2). Well then k could be 6, and the answer would be 0, or k could be 7 and the answer is 1. (2) is not sufficient.

(1) is more interesting. The question asks for the remainder when k is divided by j

k/j = X r R

Where X is the integer value of k/j and R is the remainder. But whats another way to say this? You might say that, since k>j, that k is equal to some integer times j plus the remainder. For example say k = 10 and j = 7

10/7 = 1 R 3

OR

10 = 7*1 + 3

Which is exactly what (1) is giving you. Its giving you that k = j*m + 5 where m is an integer and 5 is the remainder. But you don't know that the multiple is greater than 5, which would be necessary for this to work. (2) gives you that condition.

Hence choose (c)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 355
Joined: Thu Feb 19, 2009 12:42 pmFollowed by: 1 member
Thanked: 2 times

by vineetbatra » Wed Feb 24, 2010 4:20 pm
B is clearly insufficient.

When I look at A I think of plugging numbers. Taking a clue from B my numbers have to be above 5 and less than equal to 5

I realise that just A is not sufficient, but A and B combined are sufficient.

So C

So the takeaway from this Q is if X = Y + z then for all the values of x and Y where Y >Z, X/Y will have a remainder of Z.

Guys do you concur.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 132
Joined: Thu Dec 02, 2010 2:49 am
Thanked: 5 times

by RadiumBall » Wed Mar 16, 2011 10:13 pm
I don't know I may be missing something basic here. But how would the remainder be 5 when j > 5?

Actaully I think the remainder will be 0 when the denominator (here j) is greater than the numerator (here 5).
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Wed Mar 16, 2011 10:51 pm
RadiumBall wrote:I don't know I may be missing something basic here. But how would the remainder be 5 when j > 5?

Actaully I think the remainder will be 0 when the denominator (here j) is greater than the numerator (here 5).
Let us say j = 7 > 5.
So, when 5 is divided by 7, quotient is 0 and remainder is 5.
So, if j > 5, 5 divided by j will give quotient 0 and not remainder 0. Remainder will be 5.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 132
Joined: Thu Dec 02, 2010 2:49 am
Thanked: 5 times

by RadiumBall » Wed Mar 16, 2011 11:03 pm
Thanks :) ...Got confused between the Quotient and Remainder
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1