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ds on co-ed ratio

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by ruplun » Sat Jul 23, 2011 10:50 pm
On a co-ed Ultimate Frisbee Team, the ratio of men to women was 3 to 1 at the end of last season. If the team lost 2 men and 1 woman, and recruited 3 women, does this year's team have as many men as women?



(1) The teams for last year and this year have 12 players.



(2) Last year's team had 9 men.


Statement (1) ALONE is sufficient, but statement (2) ALONE is not sufficient.

Statement (2) ALONE is sufficient, but statement (1) ALONE is not sufficient.

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

EACH statement ALONE is sufficient.

Statements (1) and (2) TOGETHER are NOT sufficient.
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Source: — Data Sufficiency |
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by knight247 » Sat Jul 23, 2011 11:40 pm
Last year
M/W=3/1
M=3W....(a)

This year
Number of men and women are
M-2 and W-1+3= W+2

(1) Last year
M+W=12
3W+W=12
W=4 and M=8
This year, the number of men and women become 8-2 and 4+2 respectively. Both are equal to 6 hence statement 1 is sufficient.

(2)Last year M=9
M/W=3/1

M=9
W=9/3=3

This year the number of men and women becomes 9-2 and 3-1+2. 7 and 4 respectively.So no. Hence 2 is also sufficient.

D is the answer
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by ruplun » Sun Jul 24, 2011 11:49 am
Statement (1) states that this year and last years team players were 12.so its quite vague ...isnt it..
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by Ozlemg » Mon Jul 25, 2011 1:13 am
It is D.

why do you think it is vague? We have to find out that whether the ratio of W and M is %50-%50 or W:6, M:6

Statement 1 says total number of players is 12 before and now. so it helps us to figure out ratio 3:1 is, 9 M,3 W...
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by top_business_2011 » Mon Jul 25, 2011 3:20 am
ruplun wrote:On a co-ed Ultimate Frisbee Team, the ratio of men to women was 3 to 1 at the end of last season. If the team lost 2 men and 1 woman, and recruited 3 women, does this year's team have as many men as women?



(1) The teams for last year and this year have 12 players.



(2) Last year's team had 9 men.


Statement (1) ALONE is sufficient, but statement (2) ALONE is not sufficient.

Statement (2) ALONE is sufficient, but statement (1) ALONE is not sufficient.

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

EACH statement ALONE is sufficient.

Statements (1) and (2) TOGETHER are NOT sufficient.
I think the way I've approached this problem is a bit different. Here I go...

Last year:
(M/W)= (3X)/(X), Where, M= number of men last year M2=number of men this year
W= number of women last year W2= number of women this year
X= a constant. [We need this because we're given only a ratio.]
This year:
(M2/W2)= (3X-2)/(X+2)
Required:
Is X+2 = 3X -2?
This means: Is X=2?

Statement 1: The team has 12 players in both years.So take, for example, the last year:
Total players last year= 3X + X = 4X =12
X= 3
As the question asks if X is 2, here we can answer saying 'No!'. Hence, Sufficient.
Statement 2: Last year the team had 9 men
Meaning: 3x=9
x=3
Once again our answer is 'No!'. Hence, Sufficient.
The answer is D.
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by SticklorForDetails » Tue Jul 26, 2011 8:30 am
ruplun wrote: (1) The teams for last year and this year have 12 players.

Statement (1) states that this year and last years team players were 12.so its quite vague ...isnt it..
Yes, it isn't well written ... what's the source of this problem? From an SC standpoint, it's very confusing because "this year" could be construed as the subject of the sentence. It should have read "Both the team last year and the team this year have 12 players" to be clear.
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