-
cmr209
- Senior | Next Rank: 100 Posts
- Posts: 42
- Joined: Thu Sep 11, 2008 11:07 pm
- Location: California
- Thanked: 3 times
I'm stuck on this problem:
y/3 + z = 17 and y - 3z = -3
Here is how approached it:
3(y/3 + z) = 17 * 3
y + 3z = 51
y - 3z = -3
y = -48
Now I plug in -48 into the second equation.
-48 - 3z = -3
+48
-3z = -3 + 48
-3z = 45
-3z = 45
 -3      -3
z = -15
Where am I going wrong?
The answer is stated as:
z = 9
y = 3(8) = 24
y/3 + z = 17 and y - 3z = -3
Here is how approached it:
3(y/3 + z) = 17 * 3
y + 3z = 51
y - 3z = -3
y = -48
Now I plug in -48 into the second equation.
-48 - 3z = -3
+48
-3z = -3 + 48
-3z = 45
-3z = 45
 -3      -3
z = -15
Where am I going wrong?
The answer is stated as:
z = 9
y = 3(8) = 24
