Quotient/Remainder Problem

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by Seyitbek » Mon Apr 02, 2012 7:45 pm
it is E.

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by Bill@VeritasPrep » Mon Apr 02, 2012 8:27 pm
Seyitbek wrote:it is E.
The key rule here is that whenever the divisor is bigger than the dividend, the quotient is 0 and the remainder is the dividend. Essentially, since we can't factor anything out, we have the amount we started with left over.

S1 Knowing that y is between 90 and 100 is enough to know that y is bigger than 33. For illustration purposes, let's say that y=91, so our question now is "what is the remainder when 33 is divided by 91?"

How many times does 91 go into 33? 0. There's our quotient. What's our remainder? The 33 we started with. Thus, S1 is sufficient.

Statement 2 gives us a lot of possible answers. If y=2, the remainder is 1. If y=3, the remainder is 0. Insufficient.
Last edited by Bill@VeritasPrep on Mon Apr 02, 2012 8:57 pm, edited 1 time in total.
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by vikram4689 » Mon Apr 02, 2012 8:46 pm
I guess you intended that answer is A
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by Bill@VeritasPrep » Mon Apr 02, 2012 8:57 pm
vikram4689 wrote:I guess you intended that answer is A
Oops, yes. Thanks for catching that!
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