OG 12 # 112 - Correct Approach

This topic has expert replies
Source: — Data Sufficiency |

User avatar
Master | Next Rank: 500 Posts
Posts: 422
Joined: Mon Aug 09, 2010 11:47 am
Thanked: 22 times
Followed by:1 members
GMAT Score:680

by beatthegmatinsept » Fri Sep 17, 2010 4:13 pm
ankur.agrawal wrote:Can i post only using the Question no OF OG 12. Saves a lot of time typing
Members won't be able to answer it if they don't have the book handy ;)
So your response time will probably be longer :)
Being defeated is often only a temporary condition. Giving up is what makes it permanent.

User avatar
Senior | Next Rank: 100 Posts
Posts: 82
Joined: Sat Aug 21, 2010 8:18 am
Location: India
Thanked: 5 times

by sumit.sinha » Sat Sep 18, 2010 4:21 am
ankur.agrawal wrote:Can i post only using the Question no OF OG 12. Saves a lot of time typing
OK i will try. But still it is my approach :D (may not be the correct approach :P)

Let total work be A.
Let Machine X operating alone fill x part of production lot in 4 hours i.e. work done by machine X is x in 4 hours
Rate of machine X. Rx = (x/4) bottles per hour

Now Machine Y operating alone fill the remaining part of production lot i.e. work done by machine Y is (A-x) in 3 hours.
Rate of machine Y, Ry = (A-x)/3 bottles per hour

We need to know A/Rx or (A/x)4?

(1) Rx = 30 bottles per minute
i.e 1800 bottles per hour. But we don't know the value of A or x. hence INSUFFICIENT

(2) Bottles produced by machine X in 4 hours = Rx * 4 = x bottles
Bottles produced by machine Y in 3 hours = Ry * 3 = (A-x) bottles

Given that x = 2(A-x)
i.e. x = 2A - 2x
i.e. 3x = 2A
i.e A/x = 3/2
Machine X operating alone will fill the entire lot in (A/x)4 hours = (3/2) *4 = 6 hours
SUFFICIENT

CORRECT ANSWER (B)