-
givemeanid
- Master | Next Rank: 500 Posts
- Posts: 277
- Joined: Sun Jun 17, 2007 2:51 pm
- Location: New York, NY
- Thanked: 6 times
- Followed by:1 members
R = 36
S = 18
1/R + 1/S = 1/T
1/36 + 1/18 = 1/T
3/36 = 1/T
T = 12
This means, if an R and an S machine were working together, it would take them 12 hours to do the work.
To do the work in 2 hours, 12/2 = 6 of each would be needed.
Alternately,
n/R + n/S = 1/T
n/36 + n/18 = 1/2
3n/36 = 1/2
6n = 36
n = 6
S = 18
1/R + 1/S = 1/T
1/36 + 1/18 = 1/T
3/36 = 1/T
T = 12
This means, if an R and an S machine were working together, it would take them 12 hours to do the work.
To do the work in 2 hours, 12/2 = 6 of each would be needed.
Alternately,
n/R + n/S = 1/T
n/36 + n/18 = 1/2
3n/36 = 1/2
6n = 36
n = 6
So It Goes
